#+title: Assignment 6 #+options: toc:nil #+latex_header: \usepackage{parskip} #+latex_header: \usepackage{stmaryrd} #+latex_header: \usepackage{bussproofs} In order to pass this assignment you have to get at least two points. * (2p) The following string represents a Turing machine, using the encoding presented in the lectures: \[ 1001100 1 0 10 10 10 1 1 0 110 10 110 1 1 10 10 0 0 1 1 10 110 0 0 1 0 \] The following string is an encoding, using the encoding presented in the lectures, of some input to the Turing machine: \[ 110110111011011100 \] What Turing machine and what input do the strings represent? And what is the result of running the Turing machine with the given input? ** Answer The Turing machine is the one described by the following: - States: $S = \{ s_0, s_1 \}$ - Initial state: $s_0$ - Input alphabet: $\{c_1,c_2\}$ - Tape alphabet: $\{\text{\textvisiblespace}},c_1,c_2\}$ - Transition function: + $\delta (s_0, c_1) = (s_1,c_1,R)$ + $\delta (s_0, c_2) = (s_1,c_2,R)$ + $\delta (s_1, c_1) = (s_0,\text{\textvisiblespace},R)$ + $\delta (s_1, c_2) = (s_0,\text{\textvisiblespace},R)$ Running the machine on the given input, results in erasing every other character. * (2p) Implement a Turing machine interpreter using $\chi$. The interpreter should be a closed $\chi$ expression. If we denote this expression by run, then it should satisfy the following property (but you do not have to prove that it does): + For every Turing machine tm and input string $xs \in \text{List}\ \{0, 1\}$ the following equation should hold: \[ \llbracket \text{apply}\ (\text{apply}\ \text{\textit{run}}\ \ulcorner \text{tm} \urcorner) \ulcorner xs \urcorner \rrbracket = \ulcorner \llbracket \text{tm} \rrbracket\ \text{xs} \urcorner \] (The $\llbracket \_ \rrbracket$ brackets to the left stand for the $\chi$ semantics, and the $\llbracket \_ \rrbracket$ brackets to the right stand for the Turing machine semantics.) Turing machines should be represented in the following way: + States are represented as natural numbers, represented in the usual way. + The set of states is not represented explicitly, but defined implicitly by the states that are mentioned in the definition. + The input alphabet is $\{0, 1\}$, with $0$ represented by $Zero()$ and $1$ by $Suc(Zero())$. + The tape alphabet is not represented explicitly, but contains the blank character ($Blank()$), 0, 1 and a finite number of other natural numbers (represented in the usual way). + The transition function is specified by a list of rules (using the usual list constructors). Each rule has the form $Rule(s_1, x_1, s_2, x_2, d)$, where $s_1$ and $s_2$ are states, $x_1$ and $x_2$ are tape alphabet symbols, and $d$ is a direction (left is represented by $L()$ and right by $R()$). + For a given state $s_1$ and symbol $x_1$ there must be at most one rule with $s_1$ as the first component and $x_1$ as the second component. Furthermore the list of rules must be sorted lexicographically based on these two components: entries with smaller states must precede entries with larger states, and entries with equal states must be sorted based on the symbols (with blanks sorted before the natural numbers). + The value of the transition function for a given state $s$ and symbol $x$ is given by the rule with $s = s_1$ and $x = x_1$, if any: if there is no such rule, then the transition function is undefined for the given input. If there is a matching rule $Rule(s_1, x_1, s_2, x_2, d)$, then the new state is $s_2$, the symbol written is $x_2$, and the head is moved in the direction $d$ (if possible). + Finally a Turing machine is represented by $TM(s_0, \delta)$, where $s_0$ is the initial state and $\delta$ is the transition function. The input and output strings should use the usual representation of lists, with the representation specified above for the input and tape symbols. Please test that addition, implemented as in Tutorial 5, Exercise 6 (with 0 instead of #), works as it should when run on your Turing machine interpreter. A testing procedure that you can use is included in the wrapper module (documentation). ** Answer See =Turing.hs= * (2p) Prove that every Turing-computable partial function in $\mathbb{N} \rightharpoonup \mathbb{N}$ is also $\chi$ computable. You can assume that the definition of “Turing-computable” uses Turing machines of the kind used in the previous exercise. Hint: Use the interpreter from the previous exercise. Do not forget to convert the input and output to the right formats.