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@ -39,7 +39,7 @@ Implement a Turing machine interpreter using $\chi$.
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The interpreter should be a closed $\chi$ expression. If we denote this expression by run, then it should satisfy the following property (but you do not have to prove that it does):
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+ For every Turing machine tm and input string $xs \in \text{List}\ \{0, 1\}$ the following equation should hold:
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\[ \llbracket \text{apply}\ (\text{apply}\ \text{\textit{run}}\ \ulcorner \text{tm} \urcorner) \ulcorner xs \urcorner \rrbracket = \ulcorner \llbracket \text{tm} \rrbracket \text{xs} \urcorner \]
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\[ \llbracket \text{apply}\ (\text{apply}\ \text{\textit{run}}\ \ulcorner \text{tm} \urcorner) \ulcorner xs \urcorner \rrbracket = \ulcorner \llbracket \text{tm} \rrbracket\ \text{xs} \urcorner \]
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(The $\llbracket \_ \rrbracket$ brackets to the left stand for the $\chi$ semantics, and the $\llbracket \_ \rrbracket$ brackets to the right stand for the Turing machine semantics.)
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Turing machines should be represented in the following way:
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@ -57,7 +57,7 @@ The input and output strings should use the usual representation of lists, with
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Please test that addition, implemented as in Tutorial 5, Exercise 6 (with 0 instead of #), works as it should when run on your Turing machine interpreter. A testing procedure that you can use is included in the wrapper module (documentation).
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** Answer
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See =Turing.hs=
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* (2p)
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Prove that every Turing-computable partial function in $\mathbb{N} \rightharpoonup \mathbb{N}$ is also $\chi$ computable. You can assume that the definition of “Turing-computable” uses Turing machines of the kind used in the previous exercise.
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@ -1,4 +1,87 @@
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-- |
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{-# Language LambdaCase, Strict #-}
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module Interpreter.Turing where
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import Chi
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import Interpreter.Haskell -- from assignment 3
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equalExp :: Exp
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equalExp = parse
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"rec equal = \\m. \\n. case m of \
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\ { Zero() -> case n of { Blank() -> False(); Zero() -> True(); Suc(n) -> False() } \
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\ ; Suc(m) -> case n of { Blank() -> False(); Zero() -> False(); Suc(n) -> equal m n } \
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\ ; Blank() -> case n of { Blank() -> True(); Zero() -> False(); Suc(n) -> False() } \
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\ }"
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lookupExp :: Exp
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lookupExp =
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subst (Variable "equal") equalExp $ parse
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"\\s. \\head. rec lookup = \\rules. case rules of \
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\ { Nil() -> Done() \
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\ ; Cons(x,xs) -> case x of \
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\ { Rule(s1, x1, s2, x2, d) -> case equal s s1 of \
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\ { True() -> case equal head x1 of \
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\ { True() -> Trip(s2,x2,d)\
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\ ; False() -> lookup xs \
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\ } \
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\ ; False() -> lookup xs \
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\ } \
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\ }\
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\ } \
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\ "
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joinExp :: Exp
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joinExp = parse
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"rec join = \\xs. \\ys. case xs of \
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\ { Nil() -> ys \
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\ ; Cons(x,xs) -> join xs Cons(x,ys) \
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\ }"
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appendExp :: Exp
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appendExp = parse
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"rec append = \\xs. \\ys. case xs of \
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\ { Nil() -> ys \
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\ ; Cons(x,xs) -> Cons(x,append xs ys) \
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\ }"
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reverseExp :: Exp
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reverseExp =
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subst (Variable "append") appendExp $ parse
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"rec reverse = \\xs. case xs of \
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\ { Nil() -> Nil() \
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\ ; Cons(x,xs) -> append xs Cons(x,Nil())\
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\ }"
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removeLastBlanksExp :: Exp
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removeLastBlanksExp = parse
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"rec removeLastBlanks = \\xs. case xs of \
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\ { Nil() -> Nil() \
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\ ; Cons(x,xs) -> case x of \
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\ { Blank() -> removeLastBlanks xs \
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\ ; Zero() -> Cons(x,xs) \
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\ ; Suc(n) -> Cons(x,xs) \
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\ } \
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\ }\
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\ "
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runExp :: Exp
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runExp =
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subst (Variable "removeLastBlanks") removeLastBlanksExp .
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subst (Variable "reverse") reverseExp .
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subst (Variable "join") joinExp .
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subst (Variable "lookup") lookupExp $ parse
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"(rec run = \\rev. \\tm. \\tape. case tm of \
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\ { TM(state,deltas) -> case tape of \
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\ { Nil() -> run rev TM(state,deltas) Cons(Blank(), Nil()) \
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\ ; Cons(head,xs) -> case lookup state head deltas of \
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\ { Done() -> join rev (reverse (removeLastBlanks (reverse tape))) \
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\ ; Trip(s2, x2, d) -> case d of \
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\ { L() -> case rev of \
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\ { Nil() -> run Nil() TM(s2,deltas) Cons(x2,xs) \
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\ ; Cons(y,ys) -> run ys TM(s2,deltas) Cons(y,Cons(x2,xs)) \
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\ } \
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\ ; R() -> run Cons(x2,rev) TM(s2,deltas) xs \
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\ } \
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\ } \
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\ } \
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\ }) Nil()"
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@ -26,6 +26,7 @@ library
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PrintChi
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Interpreter.Haskell
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Interpreter.Self
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Interpreter.Turing
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hs-source-dirs:
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.
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